1
MHT CET 2023 12th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The derivative of $$\mathrm{f}(\tan x)$$ w.r.t. $$\mathrm{g}(\sec x)$$ at $$x=\frac{\pi}{4}$$ where $$\mathrm{f}^{\prime}(1)=2$$ and $$\mathrm{g}^{\prime}(\sqrt{2})=4$$ is

A
$$\frac{1}{\sqrt{2}}$$
B
$$\sqrt{2}$$
C
1
D
0
2
MHT CET 2023 12th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The p.m.f of random variate $$\mathrm{X}$$ is $$P(X)= \begin{cases}\frac{2 x}{\mathrm{n}(\mathrm{n}+1)}, & x=1,2,3, \ldots \ldots, \mathrm{n} \\ 0, & \text { otherwise }\end{cases}$$

Then $$\mathrm{E}(\mathrm{X})=$$

A
$$\frac{\mathrm{n}+1}{3}$$
B
$$\frac{2 \mathrm{n}+1}{3}$$
C
$$\frac{\mathrm{n}+2}{3}$$
D
$$\frac{2 n-1}{3}$$
3
MHT CET 2023 12th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The angle between the tangents to the curves $$y=2 x^2$$ and $$x=2 y^2$$ at $$(1,1)$$ is

A
$$\tan ^{-1}\left(\frac{15}{8}\right)$$
B
$$\tan ^{-1}\left(\frac{7}{8}\right)$$
C
$$\tan ^{-1}\left(\frac{3}{4}\right)$$
D
$$\tan ^{-1}\left(\frac{1}{4}\right)$$
4
MHT CET 2023 12th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

If the area of the triangle with vertices $$(1,2,0)$$, $$(1,0,2)$$ and $$(0, x, 1)$$ is $$\sqrt{6}$$ square units, then the value of $x$ is

A
1
B
2
C
3
D
4
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