1
MHT CET 2023 12th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Time period of simple pendulum on earth's surface is '$$\mathrm{T}$$'. Its time period becomes '$$\mathrm{xT}$$' when taken to a height $$\mathrm{R}$$ (equal to earth's radius) above the earth's surface. Then the value of '$$x$$' will be

A
4
B
2
C
$$\frac{1}{2}$$
D
$$\frac{1}{4}$$
2
MHT CET 2023 12th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

Consider a soap film on a rectangular frame of wire of area $$3 \times 3 \mathrm{~cm}^2$$. If the area of the soap film is increased to $$5 \times 5 \mathrm{~cm}^2$$, the work done in the process will be (surface tension of soap solution is $$\left.2.5 \times 10^{-2} \mathrm{~N} / \mathrm{m}\right)$$

A
$$9 \times 10^{-6} \mathrm{~J}$$
B
$$16 \times 10^{-6} \mathrm{~J}$$
C
$$40 \times 10^{-6} \mathrm{~J}$$
D
$$80 \times 10^{-6} \mathrm{~J}$$
3
MHT CET 2023 12th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

In Lyman series, series limit of wavelength is $$\lambda_1$$. The wavelength of first line of Lyman series is $$\lambda_2$$ and in Balmer series, the series limit of wavelength is $$\lambda_3$$. Then the relation between $$\lambda_1$$, $$\lambda_2$$ and $$\lambda_3$$ is

A
$$\lambda_1=\lambda_2+\lambda_3$$
B
$$\lambda_2=\lambda_1+\lambda_3$$
C
$$\frac{1}{\lambda_1}=\frac{1}{\lambda_2}-\frac{1}{\lambda_3}$$
D
$$\frac{1}{\lambda_1}-\frac{1}{\lambda_2}=\frac{1}{\lambda_3}$$
4
MHT CET 2023 12th May Morning Shift
MCQ (Single Correct Answer)
+1
-0

The magnetic moment of a current (I) carrying circular coil of radius '$$r$$' and number of turns '$$n$$' depends on

A
n only
B
I only
C
r only
D
$$\mathrm{n}, \mathrm{I}$$ and $$\mathrm{r}$$
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