1
MHT CET 2021 24th September Morning Shift
MCQ (Single Correct Answer)
+2
-0

The particular solution of the differential equation $$ \frac{d y}{d x}=\frac{x+y+1}{x+y-1} $$ when $$ \mathrm{x}=\frac{2}{3} $$ and $$ y=\frac{1}{3} $$ is

A
$$ 2 x+2 y-2=\log |x+y| $$
B
$$ y-x+\frac{1}{3}=\log |x+y| $$
C
$$ x+y-1=\log |x+y| $$
D
$$ 4 x-5 y-1=\log |x+y| $$
2
MHT CET 2021 24th September Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $$a \sin \theta=b \cos \theta$$, where $$a, b \neq 0$$, then $$a\cos 2 \theta+b \sin 2 \theta=$$

A
$$\mathrm{ab}$$
B
a
C
b
D
$$\frac{a}{b}$$
3
MHT CET 2021 24th September Morning Shift
MCQ (Single Correct Answer)
+2
-0

$$\vec{a}=4 \hat{i}+13 \hat{j}-18 \hat{k}, \vec{b}=\hat{i}-2 \hat{j}+3 \hat{k}$$ and $$\vec{c}=2 \hat{i}+3 \hat{j}-4 \hat{k}$$ are three vectors such that $$\vec{a}=x \vec{b}+y \vec{c}$$, then $$x+y=$$

A
$$-1$$
B
$$-2$$
C
5
D
1
4
MHT CET 2021 24th September Morning Shift
MCQ (Single Correct Answer)
+2
-0

If the lines $$\frac{x-1}{2}=\frac{y+1}{3}=\frac{z-1}{4}$$ and $$\frac{x-2}{1}=\frac{y+m}{2}=\frac{z-2}{1}$$ intersect each other, then value of m is

A
1
B
$$-$$2
C
2
D
$$-$$1
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