MHT CET 2021 20th September Morning Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2021 20th September Morning Shift

MCQ (Single Correct Answer)

-0

A differential equation for the temperature 'T' of a hot body as a function of time, when it is placed in a bath which is held at a constant temperature of 32$$^\circ$$ F, is given by (where k is a constant of proportionality)

$$\mathrm{\frac{dT}{dt}=kT-32}$$

$$\mathrm{\frac{dT}{dt}=kT+32}$$

$$\mathrm{\frac{dT}{dt}=-k(T-32)}$$

$$\mathrm{\frac{dT}{dt}=32kT}$$

MHT CET 2021 20th September Morning Shift

MCQ (Single Correct Answer)

-0

$$\int_\limits0^{\pi / 4} \log (1+\tan x) d x=$$

$$\frac{\pi}{16} \log 2$$

$$\frac{\pi}{4} \log 2$$

$$\frac{\pi}{8} \log 2$$

$$\pi \log 2$$

MHT CET 2021 20th September Morning Shift

MCQ (Single Correct Answer)

-0

A particle is moving on a straight line. The distance $$\mathrm{S}$$ travelled in time $$\mathrm{t}$$ is given by $$\mathrm{S=a t^2+b t+6}$$. If the particle comes to rest after 4 seconds at a distance of $$16 \mathrm{~m}$$. from the starting point, then the acceleration of the particle is.

$$\frac{-3}{4} \mathrm{~m} / \mathrm{sec}^2$$

$$\frac{-1}{2} \mathrm{~m} / \mathrm{sec}^2$$

$$-1 \mathrm{~m} / \mathrm{sec}^2$$

$$\frac{-5}{4} \mathrm{~m} / \mathrm{sec}^2$$

MHT CET 2021 20th September Morning Shift

MCQ (Single Correct Answer)

-0

The negation of a statement 'x $$\in$$ A $$\cap$$ B $$\to$$ (x $$\in$$ A and x $$\in$$ B)' is

x $$\in$$ A $$\cap$$ B $$\to$$ (x $$\in$$ A or x $$\in$$ B)

x $$\in$$ A $$\cap$$ B and (x $$\notin$$ A or x $$\notin$$ B)

x $$\in$$ A $$\cap$$ B or (x $$\in$$ A or x $$\in$$ B)

x $$\notin$$ A $$\cap$$ B and (x $$\in$$ A and x $$\in$$ B)