MHT CET 2021 20th September Morning Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2021 20th September Morning Shift

MCQ (Single Correct Answer)

-0

The joint equation of the pair of lines through the origin and making an equilateral triangle with the line $$x=3$$ is

$$3 x^2-y^2=0$$

$$\sqrt{3} x^2-2 x y+y^2=0$$

$$x^2-3 y^2=0$$

$$x^2+2 x y-\sqrt{3} y^2=0$$

MHT CET 2021 20th September Morning Shift

MCQ (Single Correct Answer)

-0

If 1 is added to first 10 natural numbers, then variance of the numbers so obtained is

8.25

3.87

6.5

2.87

MHT CET 2021 20th September Morning Shift

MCQ (Single Correct Answer)

-0

A random variable X has the following probability distribution

$$\mathrm{X=x}$$	0	1	2	3	4	5	6	7
$$\mathrm{P[X=x]}$$	0	$$\mathrm{k}$$	$$\mathrm{2k}$$	$$\mathrm{2k}$$	$$\mathrm{3k}$$	$$\mathrm{k^2}$$	$$\mathrm{2k^2}$$	$$\mathrm{7k^2+k}$$

then F(4) =

$$\frac{3}{10}$$

$$\frac{1}{10}$$

$$\frac{7}{10}$$

$$\frac{4}{5}$$

MHT CET 2021 20th September Morning Shift

MCQ (Single Correct Answer)

-0

A differential equation for the temperature 'T' of a hot body as a function of time, when it is placed in a bath which is held at a constant temperature of 32$$^\circ$$ F, is given by (where k is a constant of proportionality)

$$\mathrm{\frac{dT}{dt}=kT-32}$$

$$\mathrm{\frac{dT}{dt}=kT+32}$$

$$\mathrm{\frac{dT}{dt}=-k(T-32)}$$

$$\mathrm{\frac{dT}{dt}=32kT}$$

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