1
COMEDK 2024 Morning Shift
MCQ (Single Correct Answer)
+1
-0

A particle executes a simple harmonic motion of amplitude $$\mathrm{A}$$. The distance from the mean position at which its kinetic energy is equal to its potential energy is

A
0.91 A
B
0.71 A
C
0.81 A
D
0.51 A
2
COMEDK 2024 Morning Shift
MCQ (Single Correct Answer)
+1
-0

A body of mass $$5 \mathrm{~kg}$$ at rest is rotated for $$25 \mathrm{~s}$$ with a constant moment of force $$10 \mathrm{~Nm}$$. Find the work done if the moment of inertia of the body is $$5 \mathrm{~kg} \mathrm{~m}^2$$.

A
625 J
B
125 J
C
6250 J
D
1250 J
3
COMEDK 2024 Morning Shift
MCQ (Single Correct Answer)
+1
-0

In the normal adjustment of an astronomical telescope, the objective and eyepiece are $$32 \mathrm{~cm}$$ apart. If the magnifying power of the telescope is 7, find the focal lengths of the objective and eyepiece.

A
$$\mathrm{f}_{\mathrm{o}}=7 \mathrm{~cm}$$ and $$\mathrm{f}_{\mathrm{e}}=28 \mathrm{~cm}$$
B
$$f_o=28 \mathrm{~cm}$$ and $$f_e=7 \mathrm{~cm}$$
C
$$\mathrm{f}_{\mathrm{e}}=28 \mathrm{~cm}$$ and $$\mathrm{f}_{\mathrm{o}}=4 \mathrm{~cm}$$
D
$$f_o=28 \mathrm{~cm}$$ and $$f_e=4 \mathrm{~cm}$$
4
COMEDK 2024 Morning Shift
MCQ (Single Correct Answer)
+1
-0

In a given semiconductor, the ratio of the number density of electron to number density of hole is $$2: 1$$. If $$\frac{1}{7}$$th of the total current is due to the hole and the remaining is due to the electrons, the ratio of the drift velocity of holes to the drift velocity of electrons is :

A
$$\frac{2}{3}$$
B
$$\frac{3}{1}$$
C
$$\frac{3}{2}$$
D
$$\frac{1}{3}$$
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