1
COMEDK 2024 Morning Shift
MCQ (Single Correct Answer)
+1
-0

The vector equation of two lines are

$$\begin{aligned} & \vec{r}=(1-t) \hat{\imath}+(t-2) \hat{\jmath}+(3-2 t) \hat{k} \\ & \vec{r}=(s+1) \hat{\imath}+(2 s-1) \hat{\jmath}-(2 s+1) \hat{k} \end{aligned}$$

Then the shortest distance between them is

A
$$\frac{4}{29}$$
B
$$\frac{4}{\sqrt{29}}$$
C
$$\frac{8}{29}$$
D
$$\frac{8}{\sqrt{29}}$$
2
COMEDK 2024 Morning Shift
MCQ (Single Correct Answer)
+1
-0

$$ \text { If the matrix } A=\left(\begin{array}{cc} 1 & -1 \\ -1 & 1 \end{array}\right) \text { then } A^{n+1}= $$

A
$$ 2\left(\begin{array}{cc} 1 & -1 \\ -1 & 1 \end{array}\right) $$
B
$$ 2 n\left(\begin{array}{cc} 1 & -1 \\ -1 & 1 \end{array}\right) $$
C
$$ 2^{n+1}\left(\begin{array}{cc} 1 & -1 \\ -1 & 1 \end{array}\right) $$
D
$$ 2^n\left(\begin{array}{cc} 1 & -1 \\ -1 & 1 \end{array}\right) $$
3
COMEDK 2024 Morning Shift
MCQ (Single Correct Answer)
+1
-0

$$ \text { If } A=\{1,2,3,4,5\} \text { and } B=\{2,3,6,7\} \text { then number of elements in the set }(A \times B) \cap(B \times A) \text { is equal to } $$

A
20
B
10
C
4
D
5
4
COMEDK 2024 Morning Shift
MCQ (Single Correct Answer)
+1
-0

If $$ \left[\begin{array}{lll} 1 & x & 1 \end{array}\right]\left[\begin{array}{ccc} 1 & 3 & 2 \\ 2 & 5 & 1 \\ 15 & 3 & 2 \end{array}\right]\left[\begin{array}{l} 1 \\ 2 \\ x \end{array}\right]=[0] $$ then x is equal to

A
2, 14
B
$$-2,-14$$
C
7, 4
D
2, $$-14$$
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