If the enthalpy of formation of a diatomic molecule $$\mathrm{AB}$$ is $$-400 \mathrm{~kJ} / \mathrm{mol}$$ and the bond dissociation energies of $$\mathrm{A}_2$$ and $$\mathrm{B}_2$$ and $$\mathrm{AB}$$ are in the ratio $$2: 1: 2$$, what is the bond dissociation enthalpy of $$\mathrm{B}_2$$ ?
Choose the incorrect statement from the following
Given below are 4 equations showing Molar conductivities at infinite dilution of various electrolytes. Which one of them represents the correct equation?
$$\begin{aligned} & \left(\Lambda_m^0\right)_{N a B r}-\left(\Lambda_m^0\right)_{N a C l}=\left(\Lambda_m^0\right)_{\mathrm{KCl}}-\left(\Lambda_m^0\right)_{\mathrm{KBr}} \\ & \left(\Lambda_m^0\right)_{\mathrm{HCl}}+\left(\Lambda_m^0\right)_{\mathrm{KOH}}-\left(\Lambda_m^0\right)_{\mathrm{KCl}}=\left(\Lambda_m^0\right)_{\mathrm{H}_2 \mathrm{O}} \\ & \left(\Lambda_m^0\right)_{\mathrm{KBr}}-\left(\Lambda_m^0\right)_{\mathrm{NaBr}}=\left(\Lambda_m^0\right)_{\mathrm{NaBr}}-\left(\Lambda_m^0\right)_{\mathrm{Nal}} \\ & \left(\Lambda_m^0\right)_{N H_4 \mathrm{Cl}}-\left(\Lambda_m^0\right)_{\mathrm{NH}_4 \mathrm{NO}_3}=\left(\Lambda_m^0\right)_{N H_4 \mathrm{Cl}}-\left(\Lambda_m^0\right)_{N H 4 B r} \end{aligned}$$
On the basis of VSEPR theory, match the molecules listed in Column I with their shapes given in Column II.
No. | Column I | No. | Column II |
---|---|---|---|
A | $$\mathrm{ClF_3}$$ | P | Sea saw |
B | $$\mathrm{BrF_5}$$ | Q | Pentagonal bipyramidal |
C | $$\mathrm{SF_4}$$ | R | Square pyramidal |
D | $$\mathrm{IF_7}$$ | S | T-shaped |