1
COMEDK 2024 Evening Shift
MCQ (Single Correct Answer)
+1
-0

Arrange the following redox couples in the increasing order of their reducing strength:

$$\begin{array}{ll} {[\mathrm{A}]=\mathrm{Cu} / \mathrm{Cu}^{2+}} & \mathrm{E}^0=-0.34 \mathrm{~V} \\ {[\mathrm{~B}]=\mathrm{Ag} / \mathrm{Ag}^{+}} & \mathrm{E}^0=-0.8 \mathrm{~V} \\ {[\mathrm{C}]=\mathrm{Ca} / \mathrm{Ca}^{2+}} & \mathrm{E}^0=+2.87 \mathrm{~V} \\ {[\mathrm{D}]=\mathrm{Cr} / \mathrm{Cr}^{3+}} & \mathrm{E}^0=+0.74 \mathrm{~V} \end{array}$$

A
B < A < D < C
B
A < C < B < D
C
C < D < A < B
D
D < A < C < B
2
COMEDK 2024 Evening Shift
MCQ (Single Correct Answer)
+1
-0

In the presence of a catalyst at a given temperature of $$27^{\circ} \mathrm{C}$$, the Activation energy of a specific reaction is reduced by $$100 \mathrm{~J} / \mathrm{mol}$$. What is the ratio between the rate constants for the catalysed $$(\mathrm{k}_2)$$ and uncatalysed $$(\mathrm{k}_1)$$ reactions?

A
$$1.04 \times 10^{-2}$$
B
$$2.32 \times 10^{-2}$$
C
1.97
D
1.04
3
COMEDK 2024 Evening Shift
MCQ (Single Correct Answer)
+1
-0

5.0 moles of an Ideal gas at 3.0 atm pressure and $$27^{\circ} \mathrm{C}$$ is compressed isothermally to half its volume by application of an external pressure of $$3.5 \mathrm{~atm}$$. What is the amount of work done (in joules) on the gas? Given: $$1 \mathrm{~L} \mathrm{~atm}=101.3 \mathrm{~J}: \mathrm{R}=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~K}{ }^{-1} \mathrm{~mol}^{-1}$$

A
$$-3559.9$$
B
7268.3
C
$$-10367.4$$
D
14359.2
4
COMEDK 2024 Evening Shift
MCQ (Single Correct Answer)
+1
-0

Identify the products C, D and F formed in the following sets of reactions.

COMEDK 2024 Evening Shift Chemistry - Haloalkanes and Haloarenes Question 2 English

A
$$ \mathrm{C}=\mathrm{p} \text {-nitrobromobenzene } \mathrm{D}=\mathrm{m} \text {-nitrobromobenzene } \mathrm{F}=\text { o-nitrobromobenzene } $$
B
$$ \mathrm{C}=\text { o-nitrobromobenzene } \mathrm{D}=\mathrm{m} \text {-nitrobromobenzene } \quad \mathrm{F}=\mathrm{p} \text {-nitrobromobenzene } $$
C
$$ \mathrm{C}=\mathrm{o} \text {-nitrobromobenzene } \mathrm{D}=\mathrm{p} \text {-nitrobromobenzene } \mathrm{F}=\mathrm{m} \text {-nitrobromobenzene } $$
D
$$ \mathrm{C}=\mathrm{m} \text {-nitrobromobenzene } \mathrm{D}=\mathrm{p} \text {-nitrobromobenzene } \mathrm{F}=\text { o-nitrobromobenzene } $$
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