A compound having molecular formula $$\mathrm{C}_4 \mathrm{H}_{11} \mathrm{N}$$, reacts with $$\mathrm{CHCl}_3$$ in alcoholic $$\mathrm{KOH}$$, on heating, to form a compound with a foul smell. Identify the optically active isomer of the compound which also shows the above reaction.
A Hydrocarbon [A] (molecular formula $$\mathrm{C}_3 \mathrm{H}_6$$) on reaction with $$\mathrm{Br}_2 / \mathrm{CCl}_4$$ gave [B]. When [B] is heated with 2 moles of alcoholic $$\mathrm{KOH}$$, it gave compound [C]. 3 moles of Compound [C] when passed through red hot Iron tube forms [D]. Identify [D].
Identify the end-product [D] formed when solution salicylate undergoes the following series of reactions
For a given reaction, ,$$\mathrm{X}(\mathrm{g})+\mathrm{Y}(\mathrm{g} \rightarrow \mathrm{Z}(\mathrm{g})$$, the order of reaction with respect to $$\mathrm{X}$$ and $$\mathrm{Y}$$ are $$\mathrm{m}$$ and $$\mathrm{n}$$ respectively. If the concentration of $$\mathrm{X}$$ is tripled and that of $$\mathrm{Y}$$ is decreased to one third, what is the ratio between the new rate to the original rate of the reaction?