1
GATE CSE 2020
Numerical
+2
-0
Consider the following set of processes, assumed to have arrived at time 0. Consider the CPU scheduling algorithms Shortest Job First (SJF) and Round Robin (RR). For RR, assume that the processes are scheduled in the order P1, P2, P3, P4. GATE CSE 2020 Operating Systems - Process Concepts and Cpu Scheduling Question 9 English
If the time quantum for RR is 4 ms, then the absolute value of the difference between the average turnaround times (in ms) of SJF and RR (round off to 2 decimal places) is _____.
Your input ____
2
GATE CSE 2020
MCQ (Single Correct Answer)
+1
-0.33
Consider the following statements about process state transitions for a system using preemptive scheduling.

I. A running process can move to ready state.

II. A ready process can move to ready state.

III. A blocked process can move to running state.

IV. A blocked process can move to ready state.

Which of the above statements are TRUE?
A
I, II and III only
B
II and III only
C
I, II and IV only
D
I, II, III and IV
3
GATE CSE 2020
MCQ (Single Correct Answer)
+1
-0.33
Consider allocation of memory to a new process. Assume that none of the existing holes in the memory will exactly fit the process's memory requirement. Hence, a new hole of smaller size will be created if allocation is made in any of the existing holes. Which one of the following statements is TRUE?
A
The hole created by worst fit is always larger than the hole created by first fit.
B
The hole created by best fit is never larger than the hole created by first fit.
C
The hole created by first fit is always larger than the hole created by next fit.
D
The hole created by next fit is never larger than the hole created by best fit.
4
GATE CSE 2020
Numerical
+2
-0
Consider the following C functions.
int tob(int b, int* arr) {
     int i;
     for (i=0; b>0; i++) {
           if (b%2) arr[i] = 1;
           else arr[i]=0;
           b = b/2;
    }
    return (i);
}

____________________
int pp(int a, int b) {
     int arr[20];
     int i, tot = 1, ex, len;
     ex = a;
     len = tob (b, arr);
     for (i=0;  i < len; i++) {
           if (arr[i] ==1)
              tot = tot * ex;
           ex = ex * ex;
    }
    return (tot);
}

The value returned by pp (3, 4) is ________.
Your input ____
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