GATE CE 2005 | GATE CE Year Wise Previous Years Questions

GATE CE 2005

MCQ (Single Correct Answer)

-0.3

Given $$a>0,$$ we wish to calculate it reciprocal value $${1 \over a}$$ by using Newton - Raphson method for $$f(x)=0.$$ The Newton - Raphson algorithm for the function will be

$${X_{k + 1}} = {1 \over 2}\left( {{X_k} + {a \over {{X_k}}}} \right)$$

$${X_{k + 1}} = {X_k} + {a \over 2}X_k^2$$

$${X_{k + 1}} = 2{X_k} - aX_k^2$$

$${X_{k + 1}} = 2{X_k} - {a \over 2}X_k^2$$

GATE CE 2005

MCQ (Single Correct Answer)

-0.6

Given $$a>0,$$ we wish to calculate its reciprocal value $${1 \over a}$$ by using Newton - Raphson method for $$f(x)=0.$$ For $$a=7$$ and starting with $${x_0} = 0.2\,\,$$ the first two iterations will be

$$0.11,$$ $$0.1299$$

$$0.12,$$ $$0.1392$$

$$0.12,$$ $$0.1416$$

$$0.13,$$ $$0.1428$$

GATE CE 2005

MCQ (Single Correct Answer)

-0.3

The Laplace transform of a function $$f(t)$$ is $$$F\left( s \right) = {{5{s^2} + 23s + 6} \over {s\left( {{s^2} + 2s + 2} \right)}}$$$
As $$t \to \propto ,\,\,f\left( t \right)$$ approaches

$$3$$

$$5$$

$$17/2$$

$$ \propto $$

GATE CE 2005

MCQ (Single Correct Answer)

-0.6

Laplace transform of $$f\left( t \right) = \cos \left( {pt + q} \right)$$ is

$${{s\,\cos \,q - p\,\sin \,q} \over {{s^2} + {p^2}}}$$

$${{s\,\sin \,q - p\,\cos \,q} \over {{s^2} + {p^2}}}$$

$${{s\,\sin \,q + p\,\cos \,q} \over {{s^2} + {p^2}}}$$

PREVIOUS NEXT

GATE CE Papers

2024