1
KCET 2017
MCQ (Single Correct Answer)
+1
-0
The output of a step down transformers is measured to be 48 V when connected to a 12 W bulb. The value of peak current is
A
$\frac{1}{\sqrt{2}} \mathrm{~A}$
B
$\sqrt{2} \mathrm{~A}$
C
$\frac{1}{2 \sqrt{2}} \mathrm{~A}$
D
$\frac{1}{4} \mathrm{~A}$
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