A parallel plate capacitor of capacitance $$C_1$$ with a dielectric slab in between its plates is connected to a battery. It has a potential difference $$V_1$$ across its plates. When the dielectric slab is removed, keeping the capacitor connected to the battery, the new capacitance and potential difference are $$C_2$$ and $$V_2$$ respectively, Then

A parallel place capacitor is charged by connecting a $$2 \mathrm{~V}$$ battery across it. It is then disconnected from the battery and a glass slab is introduced between plates. Which of the following pairs of quantities decrease?

If a slab of insulating material (conceptual). $$4 \times 10^{-3} \mathrm{~m}$$ thick is introduced between the plates of a parallel plate capacitor, the separation between the plates has to be increased by $$3.5 \times 10^{-3} \mathrm{~m}$$ to restore the capacity to original value. The dielectric constant of the material will be

Eight drops of mercury of equal radii combine to form a big drop. The capacitance of a bigger drop as compared to each smaller drop is