BITSAT 2025 | Electromagnetic Induction Question 1 | Physics

A current $I=10 \sin (100 \pi t) A$ is passed in the first coil, which induces a maximum emf of $5 \pi \mathrm{~V}$ in second coil. The mutual inductance between the coil is

5 mH

10 mH

15 mH

2.5 mH

BITSAT 2024

MCQ (Single Correct Answer)

-1

Inside a solenoid of radius 0.5 m , magnetic field is changing at a rate of $ 50 \times 10^{-6} \mathrm{~T} / \mathrm{s} $. Acceleration of an electron placed at a distance of 0.3 m from axis of solenoid will be

$ 23 \times 10^{6} \mathrm{~ms}^{-2} $

$ 26 \times 10^{6} \mathrm{~m} / \mathrm{s}^{2} $

$ 1.3 \times 10^{9} \mathrm{~ms}^{-2} $

$ 26 \times 10^{9} \mathrm{~m} / \mathrm{s}^{2} $

BITSAT 2021

MCQ (Single Correct Answer)

-1

Two coils A and B have a mutual inductance 0.001 H. The current changes in the first coil according to the equation $$i = {i_0}\sin \omega t$$, where i₀ = 10A and $$\omega$$ = 10$$\pi$$ rads^$$-$$1. The maximum value of emf in the second coil is

0.01 $$\pi$$ V

1 $$\pi$$ V

0.1 $$\pi$$ V

0.05 $$\pi$$ V

BITSAT 2020

MCQ (Single Correct Answer)

-1

Given that in a fluorescent lamp's choke, a reverse voltage of 120 V is generated as the choke's current changes steadily from 0.50 A to 0.20 A in a time frame of 0.030 ms. Calculate the self inductance of the choke in millihenrys (mH).

12 H

12 $$\times$$ 10^$$-$$3 mH

12 $$\times$$ 10^$$-$$3 H

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