1
KCET 2018
MCQ (Single Correct Answer)
+1
-0
A 100 W bulb is connected to an AC source of $220 \mathrm{~V}, 50 \mathrm{~Hz}$. Then, the current flowing through the bulb is
A
$\frac{5}{11} \mathrm{~A}$
B
$\frac{1}{2} \mathrm{~A}$
C
2 A
D
$\frac{3}{4} \mathrm{~A}$
2
KCET 2018
MCQ (Single Correct Answer)
+1
-0
In the series $L-C-R$ circuit, the power dissipation is through
A
R
B
$L$
C
C
D
Both $L$ and $C$
3
KCET 2018
MCQ (Single Correct Answer)
+1
-0
In Karnataka, the normal domestic power supply AC is $220 \mathrm{~V}, 50 \mathrm{~Hz}$. Here, 220 V and 50 Hz refer to
A
peak value of voltage and frequency
B
ms value of voltage and frequency
C
mean value of voltage and frequency
D
peak value of voltage and angular frequency
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