The minimum length of intercept on any tangent to the ellipse $\frac{x^2}{4}+\frac{y^2}{9}=1$ cut by the circle $x^2+y^2=25$ is
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Intercepts of the plane $\vec{r} \cdot \vec{n}=d(\neq 0)$ on the coordinate axes respectively are
$\frac{\hat{i} \cdot \vec{n}}{d}, \frac{\hat{j} \cdot \vec{n}}{d}, \frac{\hat{k} \cdot \vec{n}}{d}$
$\left|\frac{\hat{i} \cdot \hat{n}}{d}\right|,\left|\frac{\hat{j} \cdot \vec{n}}{d}\right|,\left|\frac{\hat{k} \cdot \vec{n}}{d}\right|$
$\frac{d}{\hat{i} \cdot \hat{n}}, \frac{d}{\hat{j} \cdot \hat{n}}, \frac{d}{\hat{k} \cdot \hat{n}}$
$\frac{d}{\hat{i} \cdot \vec{n}}, \frac{d}{\hat{j} \cdot \vec{n}}, \frac{d}{\hat{k} \cdot \vec{n}}$
The general solution of the equation $\sin ^{100} \mathrm{x}-\cos ^{100} \mathrm{x}=1$ is
$\left\{2 n \pi+\frac{\pi}{3}: n \in I\right\}$
$\left\{n \pi+\frac{\pi}{4}: n \in I\right\}$
$\left\{n \pi \pm \frac{\pi}{2}: n \in I\right\}$
$\left\{2 \mathrm{n} \pi-\frac{\pi}{3}: \mathrm{n} \in \mathrm{I}\right\}$
If $\vec{a}=\hat{i}+\hat{j}+\hat{k}, \vec{b}=\hat{i}-\hat{j}+\hat{k}, \vec{c}=\hat{i}+2 \hat{j}-\hat{k}$, then the value of $\left|\begin{array}{lll}\vec{a} \cdot \vec{a} & \vec{a} \cdot \vec{b} & \vec{a} \cdot \vec{c} \\ \vec{b} \cdot \vec{a} & \vec{b} \cdot \vec{b} & \vec{b} \cdot \vec{c} \\ \vec{c} \cdot \vec{a} & \vec{c} \cdot \vec{b} & \vec{c} \cdot \vec{c}\end{array}\right|$ is equal to
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