1
WB JEE 2026
MCQ (More than One Correct Answer)
+2
-0
Change Language

If $f(x)=x\left(1331 x^2-3630 x+3300\right)$, then for $a=\cos ^2\left(\tan ^{-1}\left(\sin \left(\cot ^{-1} 3\right)\right)\right)$

A

$f(a+1)=2331$

B

$f^{\prime}(a)=11$

C

$\mathop {\lim }\limits_{x \to a}f(x)=1000$

D

$\int_0^a(f(x)-1000) d x=\frac{2500}{11}$

2
WB JEE 2026
MCQ (More than One Correct Answer)
+2
-0
Change Language

Let $\vec{r}=\sin x(\vec{a} \times \vec{b})+\cos y(\vec{b} \times \vec{c})+2(\vec{c} \times \vec{a})$ ,where $\vec{a}, \vec{b}$ and $\vec{c}$ are three non-coplanar vectors. It is given that $\vec{r}$ is perpendicular to $(\vec{a}+\vec{b}+\vec{c})$ .Then the possible value(s)of $\left(x^2+y^2\right)$ is/are

A

$\frac{5 \pi^2}{4}$

B

$\frac{35 \pi^2}{4}$

C

$\frac{37 \pi^2}{4}$

D

$\frac{\pi^2}{4}$

3
WB JEE 2026
MCQ (More than One Correct Answer)
+2
-0
Change Language

The parabola $y=4-x^2$ has vertex P. It intersects $x$-axis at A and B. If the parabola is translated from its initial position to a new position by moving its vertex along the line $y=x+4$, so that it intersects $x$-axis at B and C , then the abscissa of C will be

A

12

B

8

C

6

D

$\frac{7}{3}$

4
WB JEE 2026
MCQ (More than One Correct Answer)
+2
-0
Change Language

If $A_1, A_2, A_3, \ldots, A_{1006}$ be independent events such that $P\left(A_l\right)=\frac{1}{2 i},(i=1,2, \ldots, 1006)$ and the probability that none of the events occurs be $\frac{\alpha!}{2^a(\beta!)^2}$ ,then

A

$\beta$ is of the form $4 k+2, k \in I$

B

$\alpha=2 \beta$

C

$\beta$ is of the form $4 k+1, k \in I$

D

$\beta$ is a prime number