1
WB JEE 2026
MCQ (Single Correct Answer)
+1
-0.25
Change Language

Given $P(x)=x^4+a x^3+b x^2+c x+d$ such that $x=0$ is the only real root of $P^{\prime}(x)=0$. If $P(-1) < P(1)$, then in the interval $[-1,1]$.

A

$P(-1)$ is the minimum but $P(1)$ is not the maximum of $P$

B

$P(-1)$ is not minimum but $P(1)$ is the maximum of $P$

C

neither $P(1)$ is the minimum nor $P(1)$ is the maximum of P

D

$P(-1)$ is the minimum and $P(1)$ is the maximum of $P$.

2
WB JEE 2026
MCQ (Single Correct Answer)
+1
-0.25
Change Language

If $\alpha, \beta$ are the roots of the equation $x^2-p x+q=0$ and $\alpha>0, \beta>0$, then $\alpha^{\frac{1}{4}}+\beta^{\frac{1}{4}}=\left(p+6 \sqrt{p}+4 q^{\frac{1}{4}} \sqrt{p+2 \sqrt{q}}\right)^k$, where $K$ is

A

$\frac{3}{2}$

B

$\frac{1}{4}$

C

$\frac{1}{3}$

D

1

3
WB JEE 2026
MCQ (Single Correct Answer)
+1
-0.25
Change Language

If $\sum\limits_{r=1}^{\infty} \tan ^{-1}\left(\frac{1}{2 r^2}\right)=a$, then $\tan a$ is equal to

A

1

B

0

C

$\sqrt{3}$

D

$\frac{\pi}{4}$

4
WB JEE 2026
MCQ (Single Correct Answer)
+1
-0.25
Change Language

Consider a function $f(x)$ which has exactly two roots at $x=a$. If $\mathop {\lim }\limits_{x \to a}\left(\frac{\lambda f^{\prime}(x)}{f(x)}-\frac{1}{x-a}\right)=m(\neq 0)$, then the value of $\lambda$ ix

A

2

B

1

C

$\frac{1}{2}$

D

$\frac{1}{4}$