Consider the following ellipse :
$\frac{x^2}{f\left(K^2+2 K+5\right)}+\frac{y^2}{f(K+11)}=1$, where $f(x)$ is a positive decreasing function. Then the value (values) of $K$ for which the major axis coincides with $x$-axis is
$\mathrm{K}=-5$
$\mathrm{K} \in(-3,2)$
$\mathrm{K} \in(-7,-5)$
$\mathrm{K}=2$
The solution of the differential equation $2 x^2 y \frac{d y}{d x}=\tan \left(x^2 y^2\right)-2 x y^2$, given $y(1)=\sqrt{\frac{\pi}{2}}$ is
$\quad \sin \left(x^2 y^2\right)=e^{x-1}$
$\quad \sin \left(x^2 y^2\right)=e^{2(x-1)}$
$\quad \cos \left(\frac{\pi}{2}+x^2 y^2\right)+x=0$
$\sin \left(x^2 y^2\right)=1$
$$ \int \frac{\left(\sqrt[3]{x+\sqrt{2-x^2}}\right)\left(\sqrt[6]{1-x \sqrt{2-x^2}}\right)}{\sqrt[3]{1-x^2}} d x ;(x \in(0,1))= $$
$2^{\frac{1}{12}} x+c$
$2^{\frac{3}{4}} x+c$
$2^{\frac{1}{3}} x+c$
$2^{\frac{1}{6}} x+c$
Consider the function $y=f(x)$ defined implicitly by the equation $y^3-3 y+x=0$ on the interval $(-\infty,-2) \cup(2, \infty)$. The area of the region bounded by the curve $y=f(x)$, the $x$-axis and the lines $x=a, x=b$, where $-\infty< a< b< -2$ is
$\int_a^b \frac{x d x}{3\left((f(x))^2-1\right)}-b f(b)+a f(a)$
$\int_a^b \frac{x d x}{3\left((f(x))^2-1\right)}+b f(b)-a f(a)$
$\quad-\int_a^b \frac{x d x}{3\left((f(x))^2-1\right)}-b f(b)+a f(a)$
$\quad-\int_a^b \frac{x d x}{3\left((f(x))^2-1\right)}+b f(b)-a f(a)$
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