Let us define the power of a matrix $A$ as the maximum $m \in Z^{+}$such that $A^m=I$. For two matrices $A$ and $B$ if $A^5=I$ and $A B A^{-1}=B^2$, then the power of the matrix $B$ is between
20 and 24
28 and 32
36 and 40
4 and 8
If for two real numbers $\mathrm{a}, \mathrm{b}$ with $|\mathrm{a}| \leq 1$ and $|\mathrm{b}| \leq 1$,
$\frac{1}{3}+\frac{\sin ^{-1} a+\sin ^{-1} b}{4}+\frac{\left(\sin ^{-1} a+\sin ^{-1} b\right)^2}{16}+\frac{\left(\sin ^{-1} a+\sin ^{-1} b\right)^3}{64}+\cdots=\frac{2(8-3 \pi)}{3(16+3 \pi)}, \quad$ then the value of $\sin ^{-1}\left(a \sqrt{1-b^2}+b \sqrt{1-a^2}\right)$ is
$\frac{2(32+15 \pi)}{3 \pi-8}$
$\frac{-\pi}{4}$
$-\frac{3 \pi}{4}$
$\frac{1}{3}+\frac{\pi}{4}$
Let $\operatorname{det} A=\left|\begin{array}{ccc}\mathrm{l} & \mathrm{m} & \mathrm{n} \\ \mathrm{p} & \mathrm{q} & \mathrm{r} \\ \mathrm{l} & \mathrm{l} & \mathrm{l}\end{array}\right|$ If $(I-m)^2+(p-q)^2=9,(m-n)^2+(q-r)^2=16,(n-I)^2+(r-p)^2=25$, then the value of $(\operatorname{det} A)^2$ is
169
144
121
100
Let $f:(0,1) \rightarrow(0,1)$ be a differentiable function such that $f^{\prime}(x) \neq 0 \forall x \in(0,1)$ and $f\left(\frac{1}{2}\right)=\frac{\sqrt{3}}{2}$. Suppose for all $x$, $\mathop {\lim }\limits_{t \to x} \frac{\int_0^t \sqrt{1-(f(s))^2} d s-\int_0^x \sqrt{1-(f(s))^2} d s}{f(t)-f(x)}=f(x)$. Then the value of $f\left(\frac{1}{4}\right)$ belongs to
$\{\sqrt{7}, \sqrt{6}\}$
$\left\{\frac{\sqrt{7}}{2}, \frac{\sqrt{15}}{2}\right\}$
$\left\{\frac{\sqrt{7}}{4}, \frac{\sqrt{15}}{4}\right\}$
$\left\{\frac{\sqrt{7}}{3}, \frac{\sqrt{15}}{3}\right\}$
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