If $\vec{a}=\hat{i}+\hat{j}+\hat{k}, \vec{b}=\hat{i}-\hat{j}+\hat{k}, \vec{c}=\hat{i}+2 \hat{j}-\hat{k}$, then the value of $\left|\begin{array}{lll}\vec{a} \cdot \vec{a} & \vec{a} \cdot \vec{b} & \vec{a} \cdot \vec{c} \\ \vec{b} \cdot \vec{a} & \vec{b} \cdot \vec{b} & \vec{b} \cdot \vec{c} \\ \vec{c} \cdot \vec{a} & \vec{c} \cdot \vec{b} & \vec{c} \cdot \vec{c}\end{array}\right|$ is equal to
64
0
14
16
Number of elements in the range set of $f(x)=\left[\frac{x}{15}\right]\left[-\frac{15}{x}\right]$, for all $x \in(0,90$ ); (where [.] denotes the greatest integer function) is
8
7
6
5
Let 10 Bags $B_1, B_2, \ldots, B_{10}$ which contains $21,22, \ldots, 30$ different articles respectively. Then the total number of ways to bring out 10 articles from a Bag is
${ }^{31} \mathrm{C}_{20}+{ }^{21} \mathrm{C}_{10}$
${ }^{31} \mathrm{C}_{20}-{ }^{21} \mathrm{C}_{10}$
${ }^{30} \mathrm{C}_{20}-{ }^{20} \mathrm{C}_{10}$
${ }^{30} \mathrm{C}_{20}+{ }^{20} \mathrm{C}_{10}$
Let domain and range of $f(x)$ and $g(x)$ is $[0, \infty)$. If $f(x)$ is an increasing function, $g(x)$ is a decreasing function, $h(x)= f\{g(x)\}, h(0)=0$ and $p(x)=h\left(x^3-2 x^2+2 x\right)-h(4)$, then for all $x \in(0,2)$
$p(x)=-3$
$\mathrm{p}(\mathrm{x})=0$
$0< p(x)<-h(4)$
$0 \leq p(x) \leq-h(4)$
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