Consider the function $y=f(x)$ defined implicitly by the equation $y^3-3 y+x=0$ on the interval $(-\infty,-2) \cup(2, \infty)$. The area of the region bounded by the curve $y=f(x)$, the $x$-axis and the lines $x=a, x=b$, where $-\infty< a< b< -2$ is
$\int_a^b \frac{x d x}{3\left((f(x))^2-1\right)}-b f(b)+a f(a)$
$\int_a^b \frac{x d x}{3\left((f(x))^2-1\right)}+b f(b)-a f(a)$
$\quad-\int_a^b \frac{x d x}{3\left((f(x))^2-1\right)}-b f(b)+a f(a)$
$\quad-\int_a^b \frac{x d x}{3\left((f(x))^2-1\right)}+b f(b)-a f(a)$
The total number of polynomials of the form $x^3+a x^2+b x+c$ which is divisible by $x^2+1$, where $a, b, c \in\{1,2,3, \ldots ., 10\}$ is
120
45
10
15
The term independent of $x$ in the expansion of $\left(\frac{x+1}{x^{\frac{2}{3}}-x^{\frac{1}{3}}+1}-\frac{x-1}{x-x^{\frac{1}{2}}}\right)^{15}$ is equal to
5105
5005
1365
105
For a real number $y$, consider $(y)$ denotes the greatest integer less than or equal to $y$. If $f(x)=\frac{\tan (\pi[x-\pi])}{1+[x]^2}$, then
$\mathrm{f}^{\prime}(\mathrm{x})$ exists for all x
$\mathrm{f}^{\prime}(\mathrm{x})$ does not exist
$f^{\prime}(1)=\frac{\pi}{4}$
$\mathrm{f}^{\prime}(1)=-\frac{\pi}{4}$
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