If $f(x)=\frac{1+x}{1-x}$ and $A$ is a matrix such that $A^3=0$, then $f(A)=$
$1+2 \mathrm{~A}+2 \mathrm{~A}^2$
$1+2 A+A^2$
$1-2 \mathrm{~A}+\mathrm{A}^2$
$1+A+A^2$
Which of the following statements is always true?
If $f(x)$ is decreasing, then $\frac{1}{f(x)}$ is increasing
If $f(x)$ is decreasing, then $\frac{1}{f(x)}$ is also decreasing
If both $f$ and $g$ are positive functions such that $f$ is decreasing and $g$ is increasing, then $\frac{f}{g}$ is a decreasing function
If both $f$ and $g$ are positive functions such that $f$ is increasing and $g$ is decreasing then $\frac{f}{g}$ is a decreasing furnction
If $0<\alpha<\beta<\gamma<\frac{\pi}{2}$, then the equation $\frac{1}{x-\sin \alpha}+\frac{1}{x-\sin \beta}+\frac{1}{x-\sin \gamma}=0$ has
real and unequal roots
imaginary roots
real and equal roots
rational roots
On the set $\mathbb{R}$ of real numbers the relation $\rho$, defined by $\mathrm{x} \rho \mathrm{y}(\mathrm{x}, \mathrm{y} \in \mathbb{R})$ iff
$|x-y|<2$ is reflexive but neither symmetric nor transitive
$|x| \geq y$ is reflexive and transitive but not symmetric
$x>|y|$ is transitive but neither reflexive nor symmetric
$x-y<2$ is reflexive and symmetric but not transitive
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