1
WB JEE 2026
MCQ (Single Correct Answer)
+1
-0.25
Change Language

The total number of polynomials of the form $x^3+a x^2+b x+c$ which is divisible by $x^2+1$, where $a, b, c \in\{1,2,3, \ldots ., 10\}$ is

A

120

B

45

C

10

D

15

2
WB JEE 2026
MCQ (Single Correct Answer)
+1
-0.25
Change Language

The term independent of $x$ in the expansion of $\left(\frac{x+1}{x^{\frac{2}{3}}-x^{\frac{1}{3}}+1}-\frac{x-1}{x-x^{\frac{1}{2}}}\right)^{15}$ is equal to

A

5105

B

5005

C

1365

D

105

3
WB JEE 2026
MCQ (Single Correct Answer)
+1
-0.25
Change Language

For a real number $y$, consider $(y)$ denotes the greatest integer less than or equal to $y$. If $f(x)=\frac{\tan (\pi[x-\pi])}{1+[x]^2}$, then

A

$\mathrm{f}^{\prime}(\mathrm{x})$ exists for all x

B

$\mathrm{f}^{\prime}(\mathrm{x})$ does not exist

C

$f^{\prime}(1)=\frac{\pi}{4}$

D

$\mathrm{f}^{\prime}(1)=-\frac{\pi}{4}$

4
WB JEE 2026
MCQ (Single Correct Answer)
+1
-0.25
Change Language

If $\int_0^1\left(\sum_{r=1}^{2013} \frac{x}{x^2+r^2}\right)\left(\prod_{r=1}^{2013}\left(x^2+r^2\right)\right) d x=\frac{1}{2}\left[\left(\prod_{r=1}^{2013}\left(1+r^2\right)-K^2\right]\right.$, then $K$ is

A

$\frac{2013(2014)(4027)}{6}$

B

$(2013)^{2013}$

C

$(2013)!$

D

$(2013!)^2$