1
MHT CET 2026 17th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The general solution of the differential equations $\dfrac{dy}{dx} = (9x + y + 5)^2$ is...
A
$\tan^{-1}\left(\dfrac{9x + y + 5}{2}\right) = -2x + c$
B
$\tan^{-1}\left(\dfrac{9x + y + 5}{2}\right) = 2x + c$
C
$\tan^{-1}\left(\dfrac{9x + y + 5}{3}\right) = -3x + c$
D
$\tan^{-1}\left(\dfrac{9x + y + 5}{3}\right) = 3x + c$
2
MHT CET 2026 17th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
Let $\vec{a}$ and $\vec{b}$ be linearly independent vectors such that
$|\vec{a}| = \sqrt{3}, |\vec{b}| = 3$ and $|\vec{a} - \vec{b}| = 4$.
If $\vec{a} \times (2\hat{i} + 2\hat{j} - \hat{k}) = (2\hat{i} + 2\hat{j} - \hat{k}) \times \vec{b}$ and $|(\vec{a} + \vec{b}) \cdot (3\hat{i} + 4\hat{j} + 2\hat{k})| = \sqrt{\lambda}$, then $\lambda = \ldots$
A
$32$
B
$64$
C
$256$
D
$128$
3
MHT CET 2026 17th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The value of $b$ such that the scalar product of the vector $\hat{i} + \hat{j} + \hat{k}$ with the unit vector parallel to the sum of the vectors $2\hat{i} + 4\hat{j} - 5\hat{k}$ and $b\hat{i} + 2\hat{j} + 3\hat{k}$ is one, is...
A
$-2$
B
$-1$
C
$0$
D
$1$
4
MHT CET 2026 17th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $|\vec{a} \cdot \vec{b}| = |\vec{a} \times \vec{b}|$, $\vec{a} \cdot \vec{b} < 0$ and $\theta$ is the angle between $\vec{a}$ and $\vec{b}$, then the value of $\sin\theta + \tan\theta$ is...
A
$\dfrac{\sqrt{2} - 2}{2}$
B
$\dfrac{\sqrt{2} + 2}{2}$
C
$\dfrac{1 + \sqrt{2}}{2}$
D
$\dfrac{2 - \sqrt{2}}{2}$

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