1
MHT CET 2026 17th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $f(x) = \cos x\,\cos 2x\,\cos 4x\,\cos 8x\,\cos 16x$, then $f'\left(\dfrac{\pi}{4}\right) =$
A
$\text{cosec}\left(\dfrac{\pi}{4}\right)$
B
$\cos\left(\dfrac{\pi}{4}\right)$
C
$\tan\left(\dfrac{\pi}{4}\right)$
D
$0$
2
MHT CET 2026 17th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $y = \dfrac{1}{3x + 5}$, then the value of $\dfrac{d^9 y}{dx^9}$ is..
A
$\dfrac{9! \times 3^9}{(3x + 5)^9}$
B
$\dfrac{(-1)^8 \times 9! \times 3^9}{(3x + 5)^9}$
C
$\dfrac{(-1)^9 \times 9! \times 3^9}{(3x + 5)^{10}}$
D
$\dfrac{(-1)^8 \times 8! \times 3^9}{(3x + 5)^{10}}$
3
MHT CET 2026 17th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The derivative of $\tan^{-1}\left(\dfrac{\sqrt{1 + x^2} - 1}{x}\right)$ with respect to $\tan^{-1}\left(\dfrac{x}{\sqrt{1 - x^2}}\right)$ at $x = \dfrac{1}{2}$ is
A
$\dfrac{\sqrt{3}}{2}$
B
$\dfrac{1}{2}$
C
$\dfrac{\sqrt{3}}{5}$
D
$\dfrac{1}{4}$
4
MHT CET 2026 17th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $y = \sqrt{\cos x^2 + \sqrt{\cos x^2 + \sqrt{\cos x^2 + \ldots \infty}}}$ and $\dfrac{dy}{dx} = \dfrac{f(x)}{2y - 1}$ then, $\int f(x)\, dx = \ldots$
A
$\sin x^2 + c$
B
$-\sin x^2 + c$
C
$\cos x^2 + c$
D
$-\cos x^2 + c$

MHT CET Papers

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