1
MHT CET 2026 17th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $y = \sqrt{\cos x^2 + \sqrt{\cos x^2 + \sqrt{\cos x^2 + \ldots \infty}}}$ and $\dfrac{dy}{dx} = \dfrac{f(x)}{2y - 1}$ then, $\int f(x)\, dx = \ldots$
A
$\sin x^2 + c$
B
$-\sin x^2 + c$
C
$\cos x^2 + c$
D
$-\cos x^2 + c$
2
MHT CET 2026 17th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If $f(x) = \cot^{-1}\left(\dfrac{3x - x^3}{1 - 3x^2}\right)$ and $g(x) = \cos^{-1}\left(\dfrac{1 - x^2}{1 + x^2}\right)$, then $\lim\limits_{x \to a}\dfrac{f(x) - f(a)}{g(x) - g(a)}$, $\left(0 < a < \dfrac{1}{2}\right)$ is
A
$\dfrac{3}{2}$
B
$\dfrac{1}{2}$
C
$-\dfrac{3}{2}$
D
$-\dfrac{1}{2}$
3
MHT CET 2026 17th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The coordinates of the points on the curve $4y = x^2$ that are nearest to the point $(0,5)$ are ...
A
$(-2\sqrt{3}, 3)$
B
$(2\sqrt{3}, -3)$
C
$(3, 2\sqrt{3})$
D
$(2\sqrt{3}, 2)$
4
MHT CET 2026 17th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The equation of the tangent to the curve $y = \sqrt{9 - 3x^2}$ at the point where the ordinate and abscissa equal is...
A
$x - 3y + 3 = 0$
B
$3x - y - 3 = 0$
C
$x + 3y - 6 = 0$
D
$3x + y - 6 = 0$

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