1
MHT CET 2026 17th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The area of the region bounded by curves $y = \sin x, y = \cos x$ and the lines $x = 0$, $x = \dfrac{\pi}{4}$ is
A
$2\sqrt{2} - 1$
B
$\sqrt{2} - 1$
C
$2 - \sqrt{2}$
D
$\dfrac{1 - \sqrt{2}}{2}$
2
MHT CET 2026 17th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The general solution of the differential equation $\sec y + (x - e^{\sin y})\dfrac{dy}{dx} = 0$ is...
A
$e^{\sin y} = x + c$
B
$xe^{\sin y} = \dfrac{e^{2\sin y}}{2} + c$
C
$2x\cos y = e^x + c$
D
$\sin y - e^{\sin y} = c$
3
MHT CET 2026 17th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The general solution of the differential equations $\dfrac{dy}{dx} = (9x + y + 5)^2$ is...
A
$\tan^{-1}\left(\dfrac{9x + y + 5}{2}\right) = -2x + c$
B
$\tan^{-1}\left(\dfrac{9x + y + 5}{2}\right) = 2x + c$
C
$\tan^{-1}\left(\dfrac{9x + y + 5}{3}\right) = -3x + c$
D
$\tan^{-1}\left(\dfrac{9x + y + 5}{3}\right) = 3x + c$
4
MHT CET 2026 17th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
Let $\vec{a}$ and $\vec{b}$ be linearly independent vectors such that
$|\vec{a}| = \sqrt{3}, |\vec{b}| = 3$ and $|\vec{a} - \vec{b}| = 4$.
If $\vec{a} \times (2\hat{i} + 2\hat{j} - \hat{k}) = (2\hat{i} + 2\hat{j} - \hat{k}) \times \vec{b}$ and $|(\vec{a} + \vec{b}) \cdot (3\hat{i} + 4\hat{j} + 2\hat{k})| = \sqrt{\lambda}$, then $\lambda = \ldots$
A
$32$
B
$64$
C
$256$
D
$128$

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