1
MHT CET 2026 17th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If the circles $x^2 + y^2 = 16$ and $x^2 + y^2 + 2ax + 4y + 4 = 0$ touch each other internally then $a =$
A
$\dfrac{2}{3}$
B
$\dfrac{1}{56}$
C
$\dfrac{-2}{3}$
D
$\dfrac{3}{2}$
2
MHT CET 2026 17th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
If the line $3x + 4y + k = 0$ touches the ellipse $9x^2 + 16y^2 = 144$, then the value of k is.
A
$\pm 3\sqrt{2}$
B
$\pm 4\sqrt{2}$
C
$\mp 8\sqrt{2}$
D
$\mp 12\sqrt{2}$
3
MHT CET 2026 17th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
Which of the following statements is/are False?
$S_1 : \exists\, n \in N$, such that $n^2 + n + 2$ is divisible by 4.
$S_2 : \exists\, x \in N$, such that $x - 17 < 20$.
$S_3 : \forall\, n \in N, \quad x^2 + 3x - 10 = 0$.
$S_4 : \forall\, n \in N, \quad n^2 \geq 1$.
A
$S_1$ and $S_2$.
B
$S_1$ and $S_3$.
C
Only $S_3$.
D
$S_2$ and $S_4$.
4
MHT CET 2026 17th April Evening Shift
MCQ (Single Correct Answer)
+2
-0
The negation of $(p \wedge q) \rightarrow ((p \vee r) \rightarrow\, \sim q)$ is equivalent to ...
A
$p \wedge q$
B
$p \wedge\, \sim r$
C
$q \wedge (p \vee r)$
D
$\sim p \wedge\, \sim q$

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