MHT CET 2025 5th May Evening Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2025 5th May Evening Shift

MCQ (Single Correct Answer)

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The population $p$ of the city at time $t$ is given by $\frac{\mathrm{dp}}{\mathrm{dt}}=\frac{\mathrm{p}}{2}-100$. If initial population is 100 then $\mathrm{p}=$

$200+100 \mathrm{e}^{\frac{\mathrm{t}}{2}}$

$200-100 \mathrm{e}^{\frac{1}{2}}$

$300-100 \mathrm{e}^{\frac{1}{2}}$

$300+100 \mathrm{e}^{\frac{1}{2}}$

MHT CET 2025 5th May Evening Shift

MCQ (Single Correct Answer)

-0

$$ \int_0^1 \log (x+1) d x= $$

$\quad \log 2-1$

$\quad \log 2+1$

$\quad 2 \log 2+1$

$2 \log 2-1$

MHT CET 2025 5th May Evening Shift

MCQ (Single Correct Answer)

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If $A=\left[\begin{array}{lll}a & 0 & 0 \\ 0 & b & 0 \\ 0 & 0 & c\end{array}\right]$ where $a=7^x, b=7^{7^x}, c=7^{7^{7^x}}$ then $\int|A| d x$, (Where $|A|$ is the determinant of the matrix $A$ ) is equal to

$\frac{7^{7^x}}{(\log 7)^3}+\mathrm{k}$, where k is constant of integration

$\frac{7^{7^{7^x}}}{\log 7}+\mathrm{k}$, where k is constant of integration

$\frac{7^{7^{7^x}}}{(\log 7)^3}+\mathrm{k}$, where k is constant of integration

$7^{7^{7^x}}(\log 7)^3+\mathrm{k}$, where k is constant of integration

MHT CET 2025 5th May Evening Shift

MCQ (Single Correct Answer)

-0

$\int \frac{\sin 7 x}{\cos 9 x \cos 2 x} \mathrm{~d} x$ is equal to

$\log \sec (9 x)-\log \sec (2 x)+\mathrm{c}$, where c is the constant of integration

$\log \sec (9 x)+\log \sec (2 x)+\mathrm{c}$, where c is the constant of integration

$\frac{1}{9} \log \sec (9 x)-\frac{1}{2} \log \sec (2 x)+\mathrm{c}$, where c is the constant of integration

$\frac{1}{9} \log \sec (9 x)+\frac{1}{2} \log \sec (2 x)+\mathrm{c}$, where c is the constant of integration