1
MHT CET 2025 5th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

The general solutions of the equation $\tan ^2 \theta+\sec 2 \theta=1$ are

A

$\mathrm{n} \pi, \mathrm{n} \pi \pm \frac{\pi}{3}, \mathrm{n} \in \mathbb{Z}$

B

$\mathrm{n} \pi, \mathrm{n} \pi \pm \frac{\pi}{4}, \mathrm{n} \in \mathbb{Z}$

C

$\quad \frac{\mathrm{n} \pi}{4}, \frac{\mathrm{n} \pi}{4} \pm \frac{\pi}{3}, \mathrm{n} \in \mathbb{Z}$

D

$\quad \mathrm{n} \pi, \mathrm{n} \pi \pm \frac{\pi}{6}, \mathrm{n} \in \mathbb{Z}$

2
MHT CET 2025 5th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

In a triangle $A B C$, with usual notations, the sides $\mathrm{a}, \mathrm{b}, \mathrm{c}$ are such that they are roots of the equation $x^3-11 x^2+38 x-40=0$ then $\frac{\cos \mathrm{A}}{\mathrm{a}}+\frac{\cos \mathrm{B}}{\mathrm{b}}+\frac{\cos \mathrm{C}}{\mathrm{c}}=$

A
$\frac{9}{16}$
B
$\frac{3}{4}$
C
1
D
$\frac{5}{16}$
3
MHT CET 2025 5th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

The value of $\tan \left[2 \tan ^{-1} \frac{1}{5}-\frac{\pi}{4}\right]$ is

A

$\frac{5}{4}$

B

$\frac{5}{16}$

C

$\frac{-7}{17}$

D

$\frac{7}{17}$

4
MHT CET 2025 5th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $\mathrm{X} \sim \mathrm{B}(35, \mathrm{p})$ such that $7 \mathrm{P}(\mathrm{X}=0)=\mathrm{P}(\mathrm{X}=1)$ then the value of $\frac{\mathrm{P}(\mathrm{X}=15)}{\mathrm{P}(\mathrm{X}=20)}$ is equal to

A

$\frac{3125}{7776}$

B

3125

C

7776

D

$\frac{625}{1296}$

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