MHT CET 2025 5th May Evening Shift | MHT CET Year Wise Previous Years Questions

MHT CET 2025 5th May Evening Shift

MCQ (Single Correct Answer)

-0

$\int \frac{\sin 7 x}{\cos 9 x \cos 2 x} \mathrm{~d} x$ is equal to

$\log \sec (9 x)-\log \sec (2 x)+\mathrm{c}$, where c is the constant of integration

$\log \sec (9 x)+\log \sec (2 x)+\mathrm{c}$, where c is the constant of integration

$\frac{1}{9} \log \sec (9 x)-\frac{1}{2} \log \sec (2 x)+\mathrm{c}$, where c is the constant of integration

$\frac{1}{9} \log \sec (9 x)+\frac{1}{2} \log \sec (2 x)+\mathrm{c}$, where c is the constant of integration

MHT CET 2025 5th May Evening Shift

MCQ (Single Correct Answer)

-0

The solution of the equation $\frac{\mathrm{d} y}{\mathrm{~d} x}=\frac{1}{x+y+1}$ is

$x=\log (x+y+2)+\mathrm{c}$, where c is the constant of integration

$x=\log (x+y-2)+\mathrm{c}$, where c is the constant of integration

$y=\log (x+y+2)+c$, where $c$ is the constant of integration

$y=\log (x+y-2)+\mathrm{c}$, where c is the constant of integration

MHT CET 2025 5th May Evening Shift

MCQ (Single Correct Answer)

-0

A spherical balloon is filled with $4500 \pi$ cubic meters of helium gas. If a leak in the balloon causes the gas to escape at the rate of $72 \pi$ cubic meters per minute, then the rate (in meters per minute) at which the radius of the balloon decreases 49 minutes after the leakage has begun, is

$\frac{9}{7}$

$-\frac{2}{9}$

$\frac{9}{2}$

$\frac{2}{9}$

MHT CET 2025 5th May Evening Shift

MCQ (Single Correct Answer)

-0

If $x \cdot \log _e\left(\log _e x\right)-x^2+y^2=4(y>0)$, then $\frac{d y}{d x}$ at $x=\mathrm{e}$ is

$\frac{\mathrm{e}}{\sqrt{4+\mathrm{e}^2}}$

$\quad \frac{2 \mathrm{e}-1}{2 \sqrt{4+\mathrm{e}^2}}$

$\frac{1+2 e}{\sqrt{4+e^2}}$

$\quad \frac{1+2 \mathrm{e}}{2 \sqrt{4+\mathrm{e}^2}}$