1
MHT CET 2023 9th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

If $$x^2+y^2=\mathrm{t}+\frac{1}{\mathrm{t}}$$ and $$x^4+y^4=\mathrm{t}^2+\frac{1}{\mathrm{t}^2}$$, then $$\frac{\mathrm{d} y}{\mathrm{~d} x}$$ is equal to

A
$$\frac{y}{x}$$
B
$$\frac{-y}{x}$$
C
$$\frac{x}{y}$$
D
$$\frac{-x}{y}$$
2
MHT CET 2023 9th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

Two tangents to the circle $$x^2+y^2=4$$ at the points $$\mathrm{A}$$ and $$\mathrm{B}$$ meet at the point $$\mathrm{P}(-4,0)$$. Then the area of the quadrilateral $$\mathrm{PAOB}, \mathrm{O}$$ being the origin, is

A
$$2 \sqrt{3}$$ sq. units
B
$$8 \sqrt{3}$$ sq. units
C
$$4 \sqrt{3}$$ sq. units
D
$$6 \sqrt{3}$$ sq. units
3
MHT CET 2023 9th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

$$\mathrm{f}: \mathbb{R}-\left(-\frac{3}{5}\right) \rightarrow \mathbb{R}$$ is defined by $$f(x)=\frac{3 x-2}{5 x+3}$$, then $$f \circ f(1)$$ is

A
1
B
$$\frac{-13}{29}$$
C
$$\frac{13}{29}$$
D
$$-1$$
4
MHT CET 2023 9th May Morning Shift
MCQ (Single Correct Answer)
+2
-0

The value of $$\cot \left(\sum_\limits{n=1}^{23} \cot ^{-1}\left(1+\sum_\limits{k=1}^n 2 k\right)\right)$$ is

A
$$\frac{23}{25}$$
B
$$\frac{25}{23}$$
C
$$\frac{23}{24}$$
D
$$\frac{24}{23}$$
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