1
MHT CET 2023 10th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $$B=\left[\begin{array}{ccc}3 & \alpha & -1 \\ 1 & 3 & 1 \\ -1 & 1 & 3\end{array}\right]$$ is the adjoint of a $$3 \times 3$$ matrix $$\mathrm{A}$$ and $$|\mathrm{A}|=4$$, then $$\alpha$$ is equal to

A
1
B
0
C
$$-$$1
D
$$-$$2
2
MHT CET 2023 10th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $$x=3 \tan \mathrm{t}$$ and $$y=3 \sec \mathrm{t}$$, then the value of $$\frac{\mathrm{d}^2 y}{\mathrm{~d} x^2}$$ at $$\mathrm{t}=\frac{\pi}{4}$$ is

A
$$\frac{-1}{6 \sqrt{2}}$$
B
$$\frac{1}{6 \sqrt{2}}$$
C
$$\frac{1}{3 \sqrt{2}}$$
D
$$\frac{3}{2 \sqrt{2}}$$
3
MHT CET 2023 10th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

A fair die is tossed twice in succession. If $$\mathrm{X}$$ denotes the number of sixes in two tosses, then the probability distribution of $$\mathrm{X}$$ is given by

A
$$\mathrm{X=}x$$ 0 1 2
$$\mathrm{P(X=}x)$$ $$\frac{25}{36}$$ $$\frac{1}{36}$$ $$\frac{5}{18}$$
B
$$\mathrm{X=}x$$ 0 1 2
$$\mathrm{P(X=}x)$$ $$\frac{5}{18}$$ $$\frac{1}{36}$$ $$\frac{25}{36}$$
C
$$\mathrm{X=}x$$ 0 1 2
$$\mathrm{P(X=}x)$$ $$\frac{25}{36}$$ $$\frac{5}{18}$$ $$\frac{1}{36}$$
D
$$\mathrm{X=}x$$ 0 1 2
$$\mathrm{P(X=}x)$$ $$\frac{5}{18}$$ $$\frac{25}{36}$$ $$\frac{1}{36}$$
4
MHT CET 2023 10th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

The negation of the statement pattern $$\sim s \vee(\sim r \wedge s)$$ is equivalent to

A
$$s \wedge r$$
B
$$s \wedge(r \wedge \sim s)$$
C
$$s \wedge \sim r$$
D
$$s \vee(r \vee \sim s)$$
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