1
MHT CET 2023 10th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

Two lines $$\frac{x-3}{1}=\frac{y+1}{3}=\frac{z-6}{-1}$$ and $$\frac{x+5}{7}=\frac{y-2}{-6}=\frac{z-3}{4} \quad$$ intersect at the point R. Then reflection of $$\mathrm{R}$$ in the $$x y$$-plane has co-ordinates

A
$$(2,-4,-7)$$
B
$$(2,-4,7)$$
C
$$(-2,4,7)$$
D
$$(2,4,7)$$
2
MHT CET 2023 10th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

The value of $$\int \frac{\left(x^2-1\right) d x}{x^3 \sqrt{2 x^4-2 x^2+1}}$$ is

A
$$2 \sqrt{2-\frac{2}{x^2}+\frac{1}{x^4}}+\mathrm{c}$$, where $$\mathrm{c}$$ is a constant of integration.
B
$$2 \sqrt{2+\frac{2}{x^2}+\frac{1}{x^4}}+c$$, where $$\mathrm{c}$$ is a constant of integration.
C
$$\frac{1}{2} \sqrt{2-\frac{2}{x^2}+\frac{1}{x^4}}+\mathrm{c}$$, where $$\mathrm{c}$$ is a constant of integration.
D
$$2 \sqrt{2-\frac{2}{x^2}-\frac{1}{x^4}}+c$$, where $$\mathrm{c}$$ is a constant of integration.
3
MHT CET 2023 10th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

The shaded area in the figure given below is a solution set of a system of inequations. The minimum value of objective function $$3 x+5 y$$, subject to the linear constraints given by this system of inequations is

MHT CET 2023 10th May Evening Shift Mathematics - Linear Programming Question 13 English

A
19.5
B
21
C
15
D
19.8
4
MHT CET 2023 10th May Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $$\overline{\mathrm{a}}=\mathrm{m} \overline{\mathrm{b}}+\mathrm{nc}$$, where $$\overline{\mathrm{a}}=4 \hat{\mathrm{i}}+13 \hat{\mathrm{j}}-18 \hat{\mathrm{k}}, \overline{\mathrm{b}}=\hat{\mathrm{i}}-2 \hat{\mathrm{j}}+3 \hat{\mathrm{k}}, \overline{\mathrm{c}}=2 \hat{\mathrm{i}}+3 \hat{\mathrm{j}}-4 \hat{\mathrm{k}}$$, then $$\mathrm{m}+\mathrm{n}=$$

A
1
B
2
C
3
D
$$-1$$
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