1
MHT CET 2021 22th September Evening Shift
MCQ (Single Correct Answer)
+2
-0

The area bounded by the parabola $$y^2=x$$ and the line $$x+y=2$$ in the first quadrant is

A
$$\frac{7}{6}$$ sq. units
B
$$\frac{1}{6}$$ sq. units
C
$$\frac{2}{3}$$ sq. units
D
$$\frac{6}{7}$$ sq. units
2
MHT CET 2021 22th September Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $$2 \cos \theta=x+\frac{1}{x}$$, then $$2 \cos 3 \theta=$$

A
$$x^3-\frac{1}{x^3}$$
B
$$\left(x+\frac{1}{x}\right)^3$$
C
$$x+\frac{1}{x}$$
D
$$x^3+\frac{1}{x^3}$$
3
MHT CET 2021 22th September Evening Shift
MCQ (Single Correct Answer)
+2
-0

For an invertible matrix $$A$$, if $$A(\operatorname{adj} A)=\left[\begin{array}{cc}20 & 0 \\ 0 & 20\end{array}\right]$$, then $$|A|=$$

A
$$-$$200
B
200
C
$$-$$2
D
20
4
MHT CET 2021 22th September Evening Shift
MCQ (Single Correct Answer)
+2
-0

$$\int_\limits{\frac{\pi}{6}}^{\frac{\pi}{2}} \frac{\operatorname{cosec} x \cdot \cot x}{1+\operatorname{cosec}^2 x} d x=$$

A
$$\frac{\pi}{4}-\tan ^{-1} 2$$
B
$$\tan ^{-1} 1$$
C
$$\tan ^{-1} 2$$
D
$$\tan ^{-1}\left(\frac{1}{3}\right)$$
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