1
MHT CET 2021 22th September Evening Shift
MCQ (Single Correct Answer)
+2
-0

The general solution of $$\frac{d y}{d x}=\frac{x+y}{x-y}$$ is

A
$$\tan ^{-1} \frac{x}{y}+\frac{1}{2} \log \left|x^2+y^2\right|=c$$
B
$$\tan ^{-1} \frac{y}{x}+\frac{1}{2} \log \left|x^2+y^2\right|=c$$
C
$$\tan ^{-1} \frac{y}{x}-\frac{1}{2} \log \left|x^2+y^2\right|=c$$
D
$$\tan ^{-1} \frac{x}{y}-\frac{1}{2} \log \left|x^2+y^2\right|=c$$
2
MHT CET 2021 22th September Evening Shift
MCQ (Single Correct Answer)
+2
-0

A line drawn from a point $$A(-2,-2,3)$$ and parallel to the line $$\frac{x}{-2}=\frac{y}{2}=\frac{z}{-1}$$ meets the $$\mathrm{YOZ}$$ plane in point $$\mathrm{P}$$, then the co-ordinates of the point $$\mathrm{P}$$ are

A
$$(0,4,-4)$$
B
$$(0,2,2)$$
C
$$(0,-2,2)$$
D
$$(0,-4,4)$$
3
MHT CET 2021 22th September Evening Shift
MCQ (Single Correct Answer)
+2
-0

First bag contains 3 red and 5 black balls and second bag contains 6 red and 4 black balls. A ball is drawn from each bag. The probability that one ball is red and the other is black, is

A
$$\frac{41}{80}$$
B
$$\frac{21}{40}$$
C
$$\frac{3}{20}$$
D
$$\frac{3}{8}$$
4
MHT CET 2021 22th September Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $$A=\left[\begin{array}{ccc}1 & 2 & 1 \\ -1 & 1 & 3\end{array}\right]$$ and $$B=\left[\begin{array}{cc}1 & 2 \\ -3 & 1 \\ 0 & 2\end{array}\right]$$, then $$(A B)^{-1}$$

A
$$\left[\begin{array}{cc}5 & -6 \\ -4 & 5\end{array}\right]$$
B
$$\left[\begin{array}{ll}5 & 6 \\ 4 & 5\end{array}\right]$$
C
$$\left[\begin{array}{ll}-5 & 6 \\ -4 & 5\end{array}\right]$$
D
$$\left[\begin{array}{ll}-5 & -6 \\ -4 & -5\end{array}\right]$$
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