1
MHT CET 2021 22th September Evening Shift
MCQ (Single Correct Answer)
+2
-0

If $$2 \cos \theta=x+\frac{1}{x}$$, then $$2 \cos 3 \theta=$$

A
$$x^3-\frac{1}{x^3}$$
B
$$\left(x+\frac{1}{x}\right)^3$$
C
$$x+\frac{1}{x}$$
D
$$x^3+\frac{1}{x^3}$$
2
MHT CET 2021 22th September Evening Shift
MCQ (Single Correct Answer)
+2
-0

For an invertible matrix $$A$$, if $$A(\operatorname{adj} A)=\left[\begin{array}{cc}20 & 0 \\ 0 & 20\end{array}\right]$$, then $$|A|=$$

A
$$-$$200
B
200
C
$$-$$2
D
20
3
MHT CET 2021 22th September Evening Shift
MCQ (Single Correct Answer)
+2
-0

$$\int_\limits{\frac{\pi}{6}}^{\frac{\pi}{2}} \frac{\operatorname{cosec} x \cdot \cot x}{1+\operatorname{cosec}^2 x} d x=$$

A
$$\frac{\pi}{4}-\tan ^{-1} 2$$
B
$$\tan ^{-1} 1$$
C
$$\tan ^{-1} 2$$
D
$$\tan ^{-1}\left(\frac{1}{3}\right)$$
4
MHT CET 2021 22th September Evening Shift
MCQ (Single Correct Answer)
+2
-0

A spherical raindrop evaporates at a rate proportional to its surface area. If its radius originally is 3 mm. and 1 hour later has been reduced to 2 mm, then the expression of radius r of the raindrop at any time t is (where 0 $$\le$$ t < 3)

A
r = t + 5
B
r = t $$-$$ 5
C
r = 3 $$-$$ t
D
r = t + 3
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