1
COMEDK 2023 Evening Shift
MCQ (Single Correct Answer)
+1
-0

The particular solution of $$e^{\frac{d y}{d x}}=2 x+1$$ given that $$y=1$$ when $$x=0$$ is

A
$$ y=\left(x+\frac{1}{2}\right) \log |2 x+1|-x+1 $$
B
$$ y=(x+1) \log |2 x+1|-x+1 $$
C
$$ y=\left(x+\frac{1}{2}\right) \log |2 x+1|-\frac{1}{2} x+1 $$
D
$$ y=\left(x-\frac{1}{2}\right) \log |2 x+1|-x-1 $$
2
COMEDK 2023 Evening Shift
MCQ (Single Correct Answer)
+1
-0

$$ \text { If } A=\left(\begin{array}{ll} 1 & 2 \\ 0 & 1 \end{array}\right) \quad P=\left(\begin{array}{cc} \cos \theta & \sin \theta \\ -\sin \theta & \cos \theta \end{array}\right) \quad Q=P^T A P, \quad \text { then } P Q^{2014} P^T \text { is equal to } $$

A
$$ \left(\begin{array}{cc} 1 & 2^{2014} \\ 0 & 1 \end{array}\right) $$
B
$$ \left(\begin{array}{cc} 1 & 4028 \\ 0 & 1 \end{array}\right) $$
C
$$ \left(P^T\right)^{2013} A^{2014} P^{2013} $$
D
$$ P^T A^{2014} P $$
3
COMEDK 2023 Evening Shift
MCQ (Single Correct Answer)
+1
-0

$$A$$ and $$B$$ are invertible matrices of the same order such that $$\left|(A B)^{-1}\right|=8$$ if $$|A|=2$$ then $$|B|$$ is

A
6
B
16
C
4
D
$$\frac{1}{16}$$
4
COMEDK 2023 Evening Shift
MCQ (Single Correct Answer)
+1
-0

The centre of the circle passing through $$(0,0)$$ and $$(1,0)$$ and touching the circle $$x^2+y^2=9$$ is

A
$$\left(\frac{1}{2}, \frac{1}{2}\right)$$
B
$$ \left(\frac{1}{2}, \frac{3}{2}\right) $$
C
$$ \left(\frac{1}{2},-\sqrt{2}\right) $$
D
$$ \left(\frac{3}{2}, \frac{1}{2}\right) $$
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