For a reaction of the type, $$2 \mathrm{X}+\mathrm{Y} \rightarrow \mathrm{A}+\mathrm{B}$$, the following is the data collected:
Experiment | $$\mathrm{[X]}$$ | $$\mathrm{[Y]}$$ | Initial rate of formation of A |
---|---|---|---|
1 | 0.2 | 0.2 | $$12.0\times10^{-3}$$ |
2 | 0.6 | 0.4 | $$\mathrm{14.4\times10^{-2}}$$ |
3 | 0.6 | 0.8 | $$5.76\times10^{-1}$$ |
4. | 0.8 | 0.2 | $$\mathrm{4.8\times10^{-2}}$$ |
What is the overall order of the reaction?
Select the strongest base from the given compounds:
[A] p- $$\mathrm{NO}_2-\mathrm{C}_6 \mathrm{H}_4 \mathrm{NH}_2$$
[B] $$\mathrm{C}_6 \mathrm{H}_5-\mathrm{CH}_2-\mathrm{NH}_2$$
[C] $$\mathrm{m}-\mathrm{NO}_2-\mathrm{C}_6 \mathrm{H}_4 \mathrm{NH}_2$$
[D] $$\mathrm{C}_6 \mathrm{H}_5 \mathrm{NH}_2$$
The conversion of Propyne to Benzene can be brought out in 4 steps.
Choose the reagents to be used, in the proper sequential order, to bring out the conversion.
Reagents provided: alc. $$\mathrm{KOH}, \mathrm{H}_2 / \mathrm{Pd}, \mathrm{Na} /$$ dry ether, $$\mathrm{HBr}, \mathrm{HBr} /\left(\mathrm{C}_6 \mathrm{H}_5 \mathrm{CO}\right)_2 \mathrm{O}_2$$, Soda-lime, $$\mathrm{Cr}_2 \mathrm{O}_3$$ (high T and P), Conc. $$\mathrm{H}_2 \mathrm{SO}_4$$
Para and ortho hydrogen differ in: