The rate constant for a First order reaction at $$560 \mathrm{~K}$$ is $$1.5 \times 10^{-6}$$ per second. If the reaction is allowed to take place for 20 hours, what percentage of the initial concentration would have converted to products?
What would be the final product [$$\mathbf{X}$$] formed when p-Toluidine undergoes the following series of reactions?
$$\begin{aligned} & \text { P-Toluidine } \xrightarrow[\text { Pyridine }]{\left\{\mathrm{CH}_2, \mathrm{CO}_2 \mathrm{O}\right.}[\mathrm{P}] \\ & {[\mathrm{P}] \xrightarrow{\mathrm{Br}_2 / \mathrm{CH}_3 \mathrm{COOH}}[\mathrm{O}]} \\ & {[\mathrm{Q}] \xrightarrow[\Delta]{\text { dilŠ½G }}[\mathrm{R}]} \\ & {\mathrm{[R]} \xrightarrow[0^{\circ} \mathrm{C}]{\mathrm{Nan}_2 / \mathrm{HCl}}\mathrm{[S]}} \\ & {[\mathrm{S}] \xrightarrow{\mathrm{H}_2 \mathrm{PO}_2}[\mathrm{X}]} \\ \end{aligned}$$
The energy of an electron in the ground state of Hydrogen atom is $$-2.18 \times 10^{-18} \mathrm{~J}$$. What would be the energy associated with the second excited state of $$\mathrm{Li}$$ ?
Identify the incorrect statement.