In neutral medium $$\mathrm{KMnO}_4$$ oxidises $$\mathrm{MnSO}_4$$ to _________
What would be the van't Hoff factor for a solution prepared by dissolving $$3.42 \mathrm{~g}$$ of $$\mathrm{CaCl}_2$$ in $$2500 \mathrm{~ml}$$ of water having an Osmotic pressure equal to $$0.75 \mathrm{~atm}$$. at $$27^{\circ} \mathrm{C}$$ ? Molar mass of $$\mathrm{CaCl}_2=111 \mathrm{~amu}$$.
The Molar conductivity of $$0.05 \mathrm{M}$$ solution of $$\mathrm{MgCl}_2$$ is $$194.5 \mathrm{~ohm}^{-1} \mathrm{~cm}^2$$ per mole at room temperature. A Conductivity cell with electrodes having $$3.0 \mathrm{~cm}^2$$ surface area and $$1.0 \mathrm{~cm}$$ apart is filled with the solution of $$\mathrm{MgCl}_2$$. What would be the resistance offered by the conductivity cell?
The equilibrium constants for the reactions $$a, b$$, and $$c$$ are as given:
a) $$\mathrm{N}_2+3 \mathrm{H}_2=2 \mathrm{NH}_3: \mathbf{K}_1$$
b) $$\mathrm{N}_2+\mathrm{O}_2=2 \mathrm{NO}: \mathrm{K}_2$$
c) $$2 \mathrm{H}_2+\mathrm{O}_2=2 \mathrm{H}_2 \mathrm{O}: \mathbf{K}_3$$
What would be the Equilibrium constant for the reaction:
$$4 \mathrm{NH}_3+5 \mathrm{O}_2=4 \mathrm{NO}+6 \mathrm{H}_2 \mathrm{O} ; \mathbf{K}_{\mathbf{x}}$$