1
BITSAT 2023
MCQ (Single Correct Answer)
+3
-1

In an electron gun the potential difference between the filament and plate is $$4000 \mathrm{~V}$$. What will be the velocity of electron emitting from the gain?

A
$$3 \times 10^3 \mathrm{~m} / \mathrm{s}$$
B
$$3.18 \times 10^7 \mathrm{~m} / \mathrm{s}$$
C
$$3.52 \times 10^7 \mathrm{~m} / \mathrm{s}$$
D
$$3.75 \times 10^7 \mathrm{~m} / \mathrm{s}$$
2
BITSAT 2023
MCQ (Single Correct Answer)
+3
-1

An electron of mass $$m$$ and charge $$e$$ initially at rest gets accelerated by a constant field $$2 E$$. The rate of change of de-Broglie wavelength of this electron at time $$t$$ ignoring relativistic effects is

A
$$-\frac{h}{\left(2 e E t^2\right)}$$
B
$$\frac{-e h t}{2 E}$$
C
$$\left(\frac{-2 m h}{e E t^2}\right)$$
D
$$\left(\frac{-h}{e E}\right)$$
3
BITSAT 2022
MCQ (Single Correct Answer)
+3
-1

The stopping potential (V0) versus frequency $$\nu $$ of a graph for photoelectric effect in a metal. From the graph, the Plank's constant (h) is

BITSAT 2022 Physics - Dual Nature of Radiation Question 4 English

A
6.60 $$\times$$ 10$$-$$34 J-s
B
6.69 $$\times$$ 10$$-$$34 J-s
C
6.62 $$\times$$ 10$$-$$34 J-s
D
6.63 $$\times$$ 10$$-$$34 J-s
4
BITSAT 2022
MCQ (Single Correct Answer)
+3
-1

The de-Broglie wavelength of an electron moving with a velocity $$\frac{c}{3}$$ (c = 3 $$\times$$ 108 m/s) is equal to the wavelength of photon. The ratio of the kinetic energies of electron and photon is

A
1 : 4
B
1 : 3
C
1 : 2
D
2 : 1
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