In a Young's double slit experiment for a particular wavelength of light the distance between third dark and fifth bright fringe is 1.63 mm . If the distance between two slit is 1 mm and distance between slit and screen is 1 metre. Then, the wavelength of light is

Young's double slit experiment is performed in a medium of refractive index of 1.33 . The maximum intensity is $ I_{0} $. The intensity at a point on the screen, where path difference between the light coming out from slits is $ \frac{\lambda}{4} $, is

In YDSE, monochromatic light falls on a screen 1.80 m from two slits separated by 2.08 mm . The first and second order bright fringes are separated by 0.553 mm . The wavelength of light used is

In a YDSE, the light of wavelength $$\lambda=5000\mathop A\limits^o $$ is used, which emerges in phase from two slits at $$a$$ distance $$d=3 \times 10^{-7} \mathrm{~m}$$ apart. A transparent sheet of thickness $$t=1.5 \times 10^{-7} \mathrm{~m}$$ and refractive index $$\mu=1.25$$ is placed over one of the slits. What is the new angular position of the central maxima of the interference pattern, from the centre of the screen? Find the value of $$y$$.