In a cyclic $p V$ process forming $A$ square loop from $(p=1 \mathrm{~atm}, V=2 \mathrm{~L})$ to $(p=3 \mathrm{~atm}$, $V=4 \mathrm{~L})$, Then, the net heat absorbed by the gas is

The bond dissociation energies of $A_2, B_2$ and $A B$ are in the ratio $1: 4: 2$. If $\Delta H$ for formation of $A B$ from $A_2$ and $B_2$ is $-100 \mathrm{~kJ} / \mathrm{mol}$, calculate the bond dissociation energy of $B_2$.

The temperature of $$K$$ at which $$\Delta G=0$$, for a given reaction with $$\Delta H=-20.5 \mathrm{~kJ} \mathrm{~mol}^{-1}$$ and $$\Delta S=-50.0 \mathrm{~JK}^{-1} \mathrm{~mol}^{-1}$$ is