1
KCET 2023
MCQ (Single Correct Answer)
+1
-0

Identify A, B and C in the sequence.

$$\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{Br} \underset{\text { Alc. }}{\stackrel{\mathrm{KCN}}{\longrightarrow}} A \stackrel{\mathrm{LiAlH}_4}{\longrightarrow} B \stackrel{\mathrm{HNO}_2}{\longrightarrow} C$$

A
$$\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CN}, \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{NH}_2, \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{OH}$$
B
$$\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{NC}, \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{OH}, \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{NH}_2$$
C
$$\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CN}, \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}, \mathrm{C}_2 \mathrm{H}_5 \mathrm{~N}_2 \mathrm{Cl}$$
D
$$\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CN}, \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{NH}_2, \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}$$
2
KCET 2022
MCQ (Single Correct Answer)
+1
-0

In the following pairs of halogen compounds, which compound undergoes faster $$S_N 1$$ reaction?

KCET 2022 Chemistry - Haloalkanes and Haloarenes Question 7 English

A
KCET 2022 Chemistry - Haloalkanes and Haloarenes Question 7 English Option 1
B
KCET 2022 Chemistry - Haloalkanes and Haloarenes Question 7 English Option 2
C
KCET 2022 Chemistry - Haloalkanes and Haloarenes Question 7 English Option 3
D
KCET 2022 Chemistry - Haloalkanes and Haloarenes Question 7 English Option 4
3
KCET 2022
MCQ (Single Correct Answer)
+1
-0

Which one of the following chlorohydrocarbon readily undergoes solvolysis?

A
KCET 2022 Chemistry - Haloalkanes and Haloarenes Question 6 English Option 1
B
KCET 2022 Chemistry - Haloalkanes and Haloarenes Question 6 English Option 2
C
KCET 2022 Chemistry - Haloalkanes and Haloarenes Question 6 English Option 3
D
$\mathrm{CH}_2=\mathrm{CHCl}$
4
KCET 2021
MCQ (Single Correct Answer)
+1
-0

Peroxide effect is observed with the addition of $$\mathrm{HBr}$$ but not with the addition of HI to unsymmetrical alkene because

A
$$\mathrm{H}-\mathrm{I}$$ bond is stronger than $$\mathrm{H}-\mathrm{Br}$$ and is not cleaved by the free radical
B
$$\mathrm{H}-\mathrm{I}$$ bond is weaker than $$\mathrm{H}-\mathrm{Br}$$ bond so that iodine free radicals combine to form iodine molecules
C
Bond strength of $$\mathrm{HI}$$ and $$\mathrm{HBr}$$ are same but free radicals are formed in $$\mathrm{HBr}$$
D
All of the above
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