BITSAT 2024 | Electrostatics Question 3 | Physics

A dust particle of mass $ 4 \times 10^{-12} \mathrm{mg} $ in suspended in air under the influence of an electric field of $ 50 \mathrm{~N} / \mathrm{C} $ directed vertically upwards. How many electrons were removed from the neutral dust particle? [Take, $ g=10 \mathrm{~m} / \mathrm{s} $ $ { }^{2} $ ]

BITSAT 2024

MCQ (Single Correct Answer)

-1

Electric field at point $ (30,30,0) $ due to a charge of $ 0.008 \mu \mathrm{C} $ placed at origin will be, (coordinates are in cm )

$ 8000 \mathrm{NC}^{-1} $

$ 4000(\hat{\mathbf{i}}+\hat{\mathbf{j}}) \mathrm{NC}^{-1} $

$ 200 \sqrt{2}(\hat{\mathbf{i}}+\hat{\mathbf{j}}) \mathrm{NC}^{-1} $

$ 400 \sqrt{2}(\hat{\mathbf{i}}+\hat{\mathbf{j}}) \mathrm{NC}^{-1} $

BITSAT 2022

MCQ (Single Correct Answer)

-1

Which one of the following graphs represents the variation of electric potential with distance r from the centre of a non-conducting charged sphere of radius R?

BITSAT 2022 Physics - Electrostatics Question 5 English Option 1

BITSAT 2022 Physics - Electrostatics Question 5 English Option 2

BITSAT 2022 Physics - Electrostatics Question 5 English Option 3

BITSAT 2022 Physics - Electrostatics Question 5 English Option 4

BITSAT 2021

MCQ (Single Correct Answer)

-1

Four charges equal to + Q are placed at the four corners of a square and a charge ($$-$$q) is at its centre. If the system is in equilibrium, then the value of $$-$$q is

$$ - {Q \over 4}(1 + 2\sqrt 2 )$$

$${Q \over 2}(2\sqrt 2 + 1)$$

$${Q \over 4}(1 + 2\sqrt 2 )$$

$${Q \over 4}(1 + \sqrt 2 )$$

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