1
WB JEE 2023
MCQ (Single Correct Answer)
+1
-0.25
Change Language

The molecular shapes of SF$$_4$$, CF$$_4$$ and XeF$$_4$$ are

A
the same with 2, 0 and 1 lone pairs of electrons on the central atoms, respectively.
B
the same with 1, 1 and 1 lone pairs of electrons on the central atoms, respectively.
C
different with 0, 1 and 2 lone pairs of electrons on the central atoms, respectively.
D
different with 1, 0 and 2 lone pairs of electrons on the central atoms, respectively.
2
WB JEE 2023
MCQ (Single Correct Answer)
+1
-0.25
Change Language

The species in which nitrogen atom is in a state of sp hybridisation is

A
NO$$_3^-$$
B
NO$$_2$$
C
NO$$_2^+$$
D
NO$$_2^-$$
3
WB JEE 2023
MCQ (Single Correct Answer)
+1
-0.25
Change Language

The correct statement about the magnetic properties of $${\left[ {Fe{{(CN)}_6}} \right]^{3 - }}$$ and $${\left[ {Fe{F_6}} \right]^{3 - }}$$ is

A
Both are paramagnetic
B
Both are diamagnetic
C
$${\left[ {Fe{{(CN)}_6}} \right]^{3 - }}$$ is diamagnetic, $${\left[ {Fe{F_6}} \right]^{3 - }}$$ is paramagnetic
D
$${\left[ {Fe{{(CN)}_6}} \right]^{3 - }}$$ is paramagnetic, $${\left[ {Fe{F_6}} \right]^{3 - }}$$ is diamagnetic
4
WB JEE 2023
MCQ (Single Correct Answer)
+2
-0.5
Change Language

Nickel combines with a uninegative monodentate ligand (X$$^-$$) to form a paramagnetic complex [NiX$$_4$$]$$^{2-}$$. The hybridisation involved and number of unpaired electrons present in the complex are respectively

A
sp$$^3$$, two
B
dsp$$^2$$, zero
C
dsp$$^2$$, one
D
sp$$^3$$, one
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