1
WB JEE 2023
MCQ (Single Correct Answer)
+1
-0.25
Change Language

In a simple harmonic motion, let f be the acceleration and t be the time period. If x denotes the displacement, then |fT| vs. x graph will look like,

A
WB JEE 2023 Physics - Simple Harmonic Motion Question 1 English Option 1
B
WB JEE 2023 Physics - Simple Harmonic Motion Question 1 English Option 2
C
WB JEE 2023 Physics - Simple Harmonic Motion Question 1 English Option 3
D
WB JEE 2023 Physics - Simple Harmonic Motion Question 1 English Option 4
2
WB JEE 2023
MCQ (Single Correct Answer)
+1
-0.25
Change Language

WB JEE 2023 Physics - Properties of Matter Question 2 English

As shown in the figure, a liquid is at same levels in two arms of a U-tube of uniform cross-section when at rest. If the U-tube moves with an acceleration 'f' towards right, the difference between liquid heights between two arms of the U-tube will be, (acceleration due to gravity = g)

A
$$\mathrm{\frac{f}{g}a}$$
B
$$\mathrm{\frac{g}{f}a}$$
C
$$\mathrm{a}$$
D
0
3
WB JEE 2023
MCQ (Single Correct Answer)
+1
-0.25
Change Language

Six molecules of an ideal gas have velocities 1, 3, 5, 5, 6 and 5 m/s respectively. At any given temperature, if $$\mathrm{\overline V}$$ and $$\mathrm{V_{rms}}$$ represent average and rms speed of the molecules, then

A
$$\mathrm{\overline V = 5}$$ m/s
B
$$\mathrm{{V_{rms}} > \overline V}$$
C
$$\mathrm{V_{rms}^2 < {\overline V ^2}}$$
D
$$\mathrm{{V_{rms}} = \overline V}$$
4
WB JEE 2023
MCQ (Single Correct Answer)
+1
-0.25
Change Language

WB JEE 2023 Physics - Properties of Matter Question 1 English

As shown in the figure, a pump is designed as horizontal cylinder with a piston having area A and an outlet orifice having an area 'a'. The piston moves with a constant velocity under the action of force F. If the density of the liquid is $$\rho$$, then the speed of the liquid emerging from the orifice is, (assume $$\mathrm{A} > >$$ a)

A
$$\sqrt{\frac{F}{\rho A}}$$
B
$$\frac{a}{A} \sqrt{\frac{F}{\rho A}}$$
C
$$\sqrt{\frac{2 F}{\rho A}}$$
D
$$\frac{A}{a} \sqrt{\frac{2 F}{\rho A}}$$
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